2/5x^2+x-1=0

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Solution for 2/5x^2+x-1=0 equation: 


x in (-oo:+oo)

(2/5)*x^2+x-1 = 0

2/5*x^2+x-1 = 0

DELTA = 1^2-(-1*2/5*4)

DELTA = 13/5

DELTA > 0

x = ((13/5)^(1/2)-1)/(2/5*2) or x = (-(13/5)^(1/2)-1)/(2/5*2)

x = 5/4*((13/5)^(1/2)-1) or x = -5/4*((13/5)^(1/2)+1)

x in { -5/4*((13/5)^(1/2)+1), 5/4*((13/5)^(1/2)-1) }

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